Question : If $\frac{2 p}{p^2-5 p+1}=\frac{1}{10}, p \neq 0$, then the value of $\left(p+\frac{1}{p}\right)$ is:
Option 1: 10
Option 2: 25
Option 3: 1
Option 4: 15
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Correct Answer: 25
Solution :
$\frac{2 p}{p^2-5 p+1}=\frac{1}{10}$
⇒ $p^2-5 p+1$ = $20p$
⇒ $p^2-25 p+1$ = $0$
⇒ $p+\frac{1}{p}-25$ = $0$
⇒ $p+\frac{1}{p}$ = $25$
Hence, the correct answer is 25.
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