Question : If $x=93, y=93, z=94$, then the value of $(x^{2}-y^{2}+10xz+10yz)$ is:
Option 1: 104784
Option 2: 147840
Option 3: 174840
Option 4: 184740
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Correct Answer: 174840
Solution :
Given: $(x^{2}-y^{2}+10xz+10yz)$
$ =(x-y)(x+y)+10z(x+y)$
$ =(x+y)[(x-y+10z)]$
By putting the values $x = 93, y= 93,$ and $z = 94$ we get:
So, $(x^{2}-y^{2}+10xz+10yz)= (93 + 93)[(93 – 93 + 10 × 94)]$
$=$ 186 × 940
$=$ 174840
Hence, the correct answer is 174840.
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