Question : If $\frac{a}{b}=\frac{25}{6}$, then the value of $\frac{a^{2}-b^{2}}{a^{2}+b^{2}}$ is:
Option 1: $\frac{589}{661}$
Option 2: $\frac{661}{589}$
Option 3: $\frac{625}{36}$
Option 4: $\frac{589}{651}$
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Correct Answer: $\frac{589}{661}$
Solution :
Given: $\frac{a}{b}=\frac{25}{6}$
Let $a$ = 25 and $b$ = 6,
⇒ $\frac{a^{2}–b^{2}}{a^{2}+b^{2}}=\frac{25^{2}–6^{2}}{25^{2}+6^{2}}
=\frac{625–36}{625+36} =\frac{589}{661}$
Hence, the correct answer is $\frac{589}{661}$.
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