Question : If $\frac14\text{ of }\frac45+\frac95\text{ of }\frac{17}{3}-\frac{3}{10}=p$, then what is the value of $p$?
Option 1: $\frac{127}{5}$
Option 2: $\frac{177}{5}$
Option 3: $\frac{255}{2}$
Option 4: $\frac{51}{2}$
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Correct Answer: $\frac{127}{5}$
Solution :
Given expression, $\frac14\text{ of }\frac45+\frac92\text{ of }\frac{17}{3}-\frac{3}{10}=p$
⇒ $p=\frac{1}{5}+\frac{51}{2}-\frac{3}{10}$
⇒ $p=\frac{2+255-3}{10}$
⇒ $p=\frac{254}{10}=\frac{127}{5}$
Hence, the correct answer is $\frac{127}{5}$.
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