Question : If $x + 3y = 6$, what is the value of $x^3 + 27y^3 + 54 xy$?
Option 1: 264
Option 2: 258
Option 3: 216
Option 4: 220
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Correct Answer: 216
Solution :
Given: $x + 3y = 6$
Cubing both sides we get:
⇒ $x^3 + 27y^3 +3\times x\times 3y(x+3y) = 216$
⇒ $x^3 + 27y^3 +3\times x\times 3y\times 6 = 216$
$\therefore x^3 + 27y^3 +54xy = 216$
Hence, the correct answer is 216.
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