if y= a.cot^-1{ m.tan^-1(bx) } find dy/dx
Answer (1)
12th Jul, 2020
You can differentiate using the chain rule i.e., first differentiating cot^-1 and then tan^-1.
Differentiation of cot^-1(x) is -1/(1+x^2) and of tan^-1(x) is 1/(1+x^2).
So dy/dx = a.(-1/(1+(m^2).(tan^-1(bx))^2)).m.(1/(1+(b^2)(x^2))).
For a better clear picture, you can rearrange the terms as per your choice.
Hope this helps.
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