Question : In a circle with centre O, AB is a diameter and CD is a chord which is equal to the radius OC. AC and BD are extended in such a way that they intersect each other at a point P, exterior to the circle. The measure of
Option 1: 30°
Option 2: 45°
Option 3: 60°
Option 4: 90°
Correct Answer: 60°
Solution :
In the triangle, OCD is an equilateral triangle as OC = OD = CD (which are all radii of the circle).
Therefore,
Since AB is a diameter,
In triangle BCP,
In
Hence, the correct answer is 60°.
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