Question : In a mixture of 55 litres, the ratio of acid to base is 7 : 4, how much base must be added to make the mixture ratio 4 : 3?
Option 1: 5.50 litres
Option 2: 5.85 litres
Option 3: 6.25 litres
Option 4: 4.45 litres
Correct Answer: 6.25 litres
Solution :
The mixture contains acid and base equal to 7$x$ and 4$x$.
So, 7$x$ + 4$x$= 55 litres, the original volume of acid and base are 35 litres and 20 litres, respectively.
Now, according to the question,
$\frac{35}{\text{20 + Volume of Base to be added}}$ = $\frac{4}{3}$
⇒ 105 = 80 + 4(Volume of Base to be added)
⇒ Volume of Base to be added = $\frac{25}{4}$
⇒ Volume of Base to be added = 6.25 litres
Hence, the correct answer is 6.25 litres.
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