Question : In the given figure, MNP, SQP, NQR, and MSR are straight lines. $\angle$NPQ = 54° and $\angle$QRS = 68°. What is the degree measure of $\angle$SMN?
Option 1: 29°
Option 2: 38°
Option 3: 54°
Option 4: 68°
Correct Answer: 29°
Solution :
In a cyclic quadrilateral, the exterior angle equals the interior opposite angle.
⇒ $\angle$SMN = $\angle$RQS = $\theta$ (let)
The exterior angle of a triangle equals the sum of two interior opposite angles.
So, from $\triangle$MPS
$\angle$RSP = $\angle$SMP + $\angle$SPM
⇒ $\angle$RSQ = $\theta$ + 54°
Again from $\triangle$RSQ,
68° + $\theta$ + $\theta$ + 54° = 180°
⇒ 2$\theta$ = 58°
⇒ $\theta$ = 29°
Hence, the correct answer is 29°.
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