Question : In the given figure, PQRS is a trapezium in which PM || SN, NR = 9 cm, PS = 12 cm, QM = NR and NR = SN. What is the area (in cm2) of a trapezium?
Option 1: 170
Option 2: 182
Option 3: 189
Option 4: 191
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Correct Answer: 189
Solution :
The area of a trapezium = $\frac{1}{2}$ × (sum of parallel sides) × height
From the figure,
The area of a trapezium = $\frac{1}{2}$ × (PS + QR) × SN
= $\frac{1}{2}$ × (PS + PS + NR × 2) × NR
= $\frac{1}{2}$ × (PS + PS + NR × 2) × NR
= (PS + NR) × NR
= (12 + 9) × 9
= 21 × 9
= 189 cm
2
Hence, the correct answer is 189.
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