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in triangleAbc sin A3/5 sin b5/13 find sin c

b.manojyadav2006 13th Jul, 2021

Answer (1)

Heena Agrawal 13th Jul, 2021

hi..

A+ B+C = PIE

A+B = PIE - C

SIN( A+B) = SIN (PIE- C)

SINA COSB + COSA SINB = SINC

3/5 * 12/13 + 4/5 * 5/13 = SINC

SINC = (36+ 20)/ 65

sin C = 56/65

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