integrate... 5x^4/1+e^-x. this

Question

integrate with limits 3..and 1 [x-1] +[x-2] + [x-3]dx

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Answer 1

Hello Candidate,

Integration refers to basically finding the area of a curved bounded by two finite boundaries. In simple words, integration is the opposite of differentiation and follows the opposite rules during solving.

If (y= 5*x.x.x.x/4 + e*-x), so the value upon integration equals to y' =( x.x.x.x.x/4 -e*x).

Hope that you have got your answer. Best of luck for Your Future. Have a Good Day!!

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integrate... 5x^4/1+e^-x. this

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Question : Simplify the following expression.
$\{[(x-5)(x-1)]-[(9 x-5)(9x-1)]\} \div 16x$
Option 1: $2x(5x-3)$
Option 2: $-(5x-3)$
Option 3: $x(5x-3)$
Option 4: $-6x(5x-3)$

Question : If $(x+\frac{1}{x})$ = 5, then the value of $\frac{5x}{x^{2}+5x+1}$ is:
Option 1: $\frac{1}{3}$
Option 2: $\frac{1}{4}$
Option 3: $\frac{1}{2}$
Option 4: $\frac{1}{5}$