Question : $2\sqrt[3]{40}-4\sqrt[3]{320}+3\sqrt[3]{625}-3\sqrt[3]{5}$ is equal to:
Option 1: $-2\sqrt[3]{340}$
Option 2: $0$
Option 3: $\sqrt[3]{340}$
Option 4: $\sqrt[3]{660}$
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Correct Answer: $0$
Solution :
$2\sqrt[3]{40}-4\sqrt[3]{320}+3\sqrt[3]{625}-3\sqrt[3]{5}$
= $2\sqrt[3]{2^3×5}-4\sqrt[3]{4^3×5}+3\sqrt[3]{5^3×5}-3\sqrt[3]{5}$
= $4\sqrt[3]{5}-16\sqrt[3]{5}+15\sqrt[3]{5}-3\sqrt[3]{5}$
= $19\sqrt[3]{5}-19\sqrt[3]{5}$
= $0$
Hence, the correct answer is $0$.
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