june monthly test 10th std 2025

can you specify under which board you are studying, so that i can help you better

The pH of a \(0.1\text{ M}\) sodium bicarbonate (\(\text{NaHCO}_{3}\)) solution is \(\text{pH} = \frac{\text{p}K_1 + \text{p}K_2}{2}\) , which can also be written in terms of the given dissociation constants as \(-\frac{1}{2}\log(ab)\)

Could you please specify which Class 7 scholarship you are referring to? Once you share the exact scholarship name, I'll help you with the result status and the process to check it.