Let alpha be the angle in radiance between x square \36+y square /4=1 and the circle xsqyare + ysquare =12 at their point of interestion if alpha = taninverse k/2root3
then the value of k is

Question

Let alpha be the angle in radiance between x square \36+y square /4=1 and the circle xsqyare + ysquare =12 at their point of interestion if alpha = taninverse k/2root3
 then the value of k is

Ayush · Accepted Answer

Hi Candidate,

The equation for ellipse is given by X2/36 + y2/4 =1, and the equation for circle is X2+y2=12. Now the point of intersection is = y=+√3,-√3 and x=+3,-3.

The value of M1 for the ellipse = -x/9y= -1/3√3. The value of M2 for circle is =-x/y= -√3. So, the value of angle is= |M1- M2/ 1+MI*M2| = -4/√3. So, the value of K = -8.

Hope that this answer helps you.

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Let alpha be the angle in radiance between x square \36+y square /4=1 and the circle xsqyare + ysquare =12 at their point of interestion if alpha = taninverse k/2root3 then the value of k is

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