My jee mains paper 2 , NTA score is 99.10 what will be my approximate rank.

Hello.

Congratulations on your terrific performance. Your expected rank is about 1300, you can easily get a seat in the NITs, however the final rank may vary as only the best of the two scores will be considered for the final rankings.

Hope this helps.

Hello Aspirant.
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. firstly congratulations for your percentile score!!!

Use this formula to predict the rank:
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Rank Formula = (100 - your total score) X 145386 /100.
Your rank is 1308 by using above formula you definitely get good College as per previous years trends.
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Your rank may differ from the official cutoff and results which were released on the month of April by national testing agency NTA officially.
You have to wait for the official results.if you want to compare with previous years cutoff of b.arch .you can go through the below link:
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https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning
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If you have any questions further let me know.
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Thank you!!!!

Hey.
You can use the formula given below to calculate JEE B.Arch Rank from your percentile-
(100- your total percentile score) * 1,45,386/ 100.
According to your percentile, on applying this formula you can expect a rank around 1300.  This is only a probable rank. You can expect a rank in a similar range. Also, the ranks are expected to change after considering the Results of the April session as the rank list will be prepared after considering the scores of both the sessions.
Best of luck