quartz crystal has thickness 0.005 m vibrating at fundamental frequency. Give the young modules for quartz as7.9×1010 N/m2 the density of quartz 2650 kg/m3 .
Answer (1)
16th Jun, 2021
Greetings dear aspirant
Given Data : t1 = 0.005m, Y = 7.9×10^10 N/m^2, Density (rho) = 2650 kg/m^3
Formula : f = 1/2t *(√Y/rho)
f = 1/2*0.005 * (√7.9×10^10/2650)
f = 1/0.01 * 5459.98
f = 0.55 MHz
Therefore, the fundamental frequency of the given quartz crystal is 0.55 Mega Hertz.
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