Question : Rs.11,500 has to be divided between X, Y, and Z such that X gets $\frac{4}{5}$th of what Y gets and Y gets $\frac{2}{3}$rd of what Z gets. How much more does Z get over X (in Rs.)?
Option 1: 7200
Option 2: 1800
Option 3: 1170
Option 4: 2450
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Correct Answer: 2450
Solution :
Given: Rs.11,500 has to be divided between X, Y, and Z such X gets $\frac{4}{5}$th of what Y gets and Y gets $\frac{2}{3}$rd of what Z gets.
Let Z get Rs. $p$.
From the question, Y will get $\frac{2p}{3}$ and X will obtain $\frac{2p}{3}×\frac{4}{5}=\frac{8p}{15}$
Also, X + Y + Z = 11550
⇒ $\frac{8p}{15}+\frac{2p}{3}+p=11550$
⇒ $\frac{8p+10p+15p}{15}=11550$
⇒ $\frac{33p}{15}=11550$
⇒ $p=5250$
So, the amount Z receives more than X $=p-\frac{8p}{15}=\frac{7p}{15}=\frac{7\times5250}{15}=2450$
Thus, Z surpasses X by Rs. 2450.
Hence, the correct answer is 2450.
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