show that the memory addressing capability of a CPU is equal to 2n bytes ,where n is the number of address line of the CPU

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show that the memory addressing capability of a CPU is equal to 2n bytes ,where n is the number of address line of the  CPU

Abhishek Roy · Accepted Answer

Hey!There

For 'n' number of address line there will be 2^n number of register as total number of combination arises with n number of (0 and 1) is 2^n.It is very simple combination.

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show that the memory addressing capability of a CPU is equal to 2n bytes ,where n is the number of address line of the CPU

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show that the memory addressing capability of a CPU is equal to 2n bytes ,where n is the number of address line of the CPU

Related Questions

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Sigma n=1to infinity (2n^2+7n+5)/n factorial is equal to

What is the difference between x less than n and x less than or equal to n on the number line?

the remainder of n^4-2n^3-n^2+2n-26 when divided by 24 is

test the convergence of sigma 2n-1÷n(n+1)(n+2)

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