Question : Simplify the following.
$\cot13° \cot27° \cot45° \cot63° \cot77° = ?$
Option 1: $1$
Option 2: $\sqrt3$
Option 3: $2$
Option 4: $\sqrt2$
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Correct Answer: $1$
Solution :
Given expression: $\cot13° \cot27° \cot45° \cot63° \cot77°$
We know $\cot (90°-\theta)=\tan \theta$
Now, $\cot13° \cot27° \cot45° \cot63° \cot77°$
= $\cot 13°\cot27°\cot45°\cot(90°-27°)\cot(90°-13°)$
= $\cot 13°\cot27°\cot45°\tan27°\tan13°$
= $\cot 45°$ [since $\cot\theta\cdot\tan\theta = 1$]
= $1$
Hence, the correct answer is $1$.
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