Question : Some staff promised to do a job in 18 days, but 6 of them went on leave. So the remaining men took 20 days to complete the job. How many men were there originally?
Option 1: 55
Option 2: 62
Option 3: 56
Option 4: 60
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Correct Answer: 60
Solution :
Let the total number of men be $x$.
The work is the same. So, $W_1=W_2=1$
Use the following formula to solve the question:
$\frac{M_{1}\times D_{1}}{W_{1}}=\frac{M_{2}\times D_{2}}{W_{2}}$
Where $M_1$ and $M_2$ are men, $D_1$ and $D_2$ are days and $W_1$ and $W_2$ are work done.
$\frac{x×18}{1}=\frac{(x-6)20}{1}$
$⇒ 18x= 20x-120$
$⇒ 2x = 120$
$\therefore x= 60$
Hence, the correct answer is 60.
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