Question : Square of $3(6-2x)$ is:
Option 1: $(12x^{2}-72x+108)$
Option 2: $(4x^{2}-24x+36)$
Option 3: $(108-72x-12x^{2})$
Option 4: $(36x^{2}-216x+324)$
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Correct Answer: $(36x^{2}-216x+324)$
Solution :
Given: $3(6-2x)$
Squaring the expression, we get,
$=(3(6-2x))^{2}$
$=9(4x^{2}+36-24x)$
$=(36x^{2}-216x+324)$
Hence, the correct answer is $(36x^{2}-216x+324)$.
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