Question : The average of 5 consecutive integers starting with 'm' is n. What is the average of 6 consecutive integers starting with (m + 2)?
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution :
Average of 5 consecutive integers starting with 'm' = n
Let m, m + 1, m + 2, m + 3, m + 4 be the 5 consecutive integers.
Average of 5 consecutive integers = middle term
Then 6 consecutive integers starting with (m + 2)
⇒ m + 2, m + 3, m + 4, m + 5, m + 6, m + 7
From equation (i),
⇒
Average of 6 consecutive integers = average of two middle terms
=
=
The average of 6 consecutive integers starting with (m + 2) is
Hence, the correct answer is
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