Question : The average of the largest and smallest 3-digit numbers formed by 0, 2 and 4 would be:
Option 1: 312
Option 2: 213
Option 3: 222
Option 4: 303
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Correct Answer: 312
Solution :
Given: Digits to form a 3-digit number are 0, 2, and 4.
According to the question,
The largest number using the given digits will be 420.
The smallest number using the given digits will be 204.
Average $ = \frac{(420 + 204)}{2} = 312$
Hence, the correct answer is 312.
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