298 Views

The degree of dissociation of N2O4 in N2O4->2NO2 is k.If initial moles of N2O4 is one the total number of moles at equilibrium

Sai 17th Apr, 2020

Answer (1)

Sandeep varma 17th Apr, 2020

If the volume of the container is taken as 1 litre then

C(initial concentration)=1/1=1

K=((Cx)^2)/C(1-x) = C(x^2)/(1-x)

where x = degree of dissociation

Find x from the equation.

Also if K is very small, then approximately,

x = (K/C)^(1/2)

Finally

total no. of moles at equilibrium = C(1-x) + 2Cx = C(1+x)

I hope you understand it.

Share

Facebook Copy Link

More

Comments (0)

Related Questions

At 90 degree celsius the vapour density of N2O4 is 24.8(H=1).calculate the degree of dissociation at this temperature.

1788 Views

The vapour density of N2O4 at a certain temp is 30. What is the percentage dissociation of N2O4 At this temp?

8070 Views

1 mole of N2 and 3 moles of H2 produces NH3 at equilibrium calculate the concentration of NH3 at equilibrium if Kc = 4/27

2867 Views

The equilibrium A(g) + B(g) = AB4 (g) is attained by mixing equal moles of A & B in a 1 litre vessel . Then at equilibrium?

2261 Views

calculate total number of moles of atoms present in 49g H2SO4

17005 Views

Link Copied

The question have been saved in answer later, you can access it from your profile anytime. Access now

Thanks! Your report is submitted, the author will be informed about it

Download Careers360 App

All this at the convenience of your phone

Regular Exam Updates
Best College Recommendations
College & Rank predictors
Detailed Books and Sample Papers
Question and Answers