Question : The following bar chart shows the quantity (in million kg ) of grains exported by India from 2018-2022.
By how much percentage is the minimum export less than the average export in the given period?
Option 1: 67.74%
Option 2: 77.25%
Option 3: 88.25%
Option 4: 38.44%
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Correct Answer: 67.74%
Solution :
Total export during the period = 47000 + 59000 + 99000 + 20000 + 85000 = 310000 (in million kg)
Average $=\frac{\text{Total export}}{\text{Total number of years}} = \frac{310000}{5}=62000$ (in million kg)
Minimum export = 20000 (in million kg)
So, Difference = 62000 – 20000 = 42000 (in million kg)
Required percentage
= $\frac{\text{Difference}}{\text{Average of total export}}\times 100$
= $\frac{42000}{62000}\times 100$ = $67.74$%
Hence, the correct answer is 67.74%.
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