Question : The HCF of three numbers 72, 108, and 2010 is:
Option 1: 18
Option 2: 6
Option 3: 12
Option 4: 5
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Correct Answer: 6
Solution :
Prime factors of
$72 = 2\times 2\times 2\times 3\times 3$
$108 = 2\times 2\times 3\times 3\times 3$
$2010 = 2\times 3\times 5\times 67$
$\therefore$ HCF of 72, 108, and 2010 is 2$\times$3 which is equal to 6.
Hence, the correct answer is 6.
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