Question : The maximum value of $5+20x-4x^{2}$, when $x$ is a real number, is:
Option 1: 1
Option 2: 5
Option 3: 25
Option 4: 30
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Correct Answer: 30
Solution :
Given: $5+20x-4x^{2}$
If an expression is in the form of $ax^{2}+bx+c$, then the maximum value is given by ($c-\frac{b^2}{4a}$).
Here, $c = 5$, $b = 20$ and $a = -4$
$\therefore$ Maximum value = $5-\frac{20^2}{4×(–4)}$
= $5 - \frac{400}{–16}$
= $5-(-25)$
= $30$
Hence, the correct answer is 30.
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