Question : The minimum value of, $\sin^2\theta+\cos^2\theta+\sec^2\theta+\operatorname{cosec}^2\theta+\tan^2\theta+\cot^2\theta$ is:
Option 1: 1
Option 2: 3
Option 3: 5
Option 4: 7
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Correct Answer: 7
Solution :
Given: $\sin^2\theta + \cos^2\theta+\sec^2\theta+\operatorname{cosec}^2\theta+\tan^2\theta+\cot^2\theta$
= $(1+\sec^2\theta+\operatorname{cosec}^2\theta+\tan^2\theta+\cot^2\theta)$
= $(1+1+\tan^2\theta+1+\cot^2\theta+\tan^2\theta+\cot^2\theta)$
= $(3+2\tan^2\theta+2\cot^2\theta)$
= $3+2(\tan^2\theta+\cot^2\theta)$
The value of the above expression is minimum when $\tan^2\theta+\cot^2\theta$ is minimum.
We know that $\tan^2\theta+\cot^2\theta \geq 2$
So, the minimum value is [3 + (2 × 2)] = 7
Hence, the correct answer is 7.
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