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the period of sin( x+8x+27x+... n^3x) is

sadashivareddy946 27th Sep, 2020

Answer (1)

Ishani J 27th Sep, 2020

Hello !

f(x)= sin [{n*(n+1)/2}^2x]

we already know that period of f(ax+b) is T/|a|.

so, since period of sin is 2pi, the period of f(x) will be 8pi/[n*(n+1)]^2

Hope this helped!

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