the rate of work of Rehman I'd twice that of sohail . Rehman alone can do a piece of work in 32 days .sohail started the work and Rehman joined him after a few days . if the entire work was completed in 24 days ,for how many days did Rehman work along with sohail
Hello,
It is given that the rate of work of Rehman is twice that of Sohail.
Rehman alone does the particular work in 32 days. So, the rate of work of Rehman is 1/32
So, the rate of work of Sohail will be 1/64
Sohail starts the work and Rehman joins few days after him. Let, Rehman worked along with Sohail for x days. The work was completed in 24 days.
So, Sohail worked alone for 24 - x days.
So, the total work done will be equal to the work done by Sohail alone + work done by Rehman and Sohail together.
Work done by Sohail alone = ( 24 - x ). ( 1/64)
Work done together = x. [ (1/32) + ( 1/64) ]
So, [( 24 - x ). ( 1/64 ) ]+ { x. [ ( 1/32 ) + ( 1/64 )] }
So, ( 24 - x / 64 ) + ( 3x / 64 ) = 1
So, 24 - x + 3x = 64
So, 2x = 40
So, x = 20
Hence, Rehman worked along with Sohail for 20 days.
Best Wishes.



