Question : The ratio of the area of a square and that of a circle, when the length of a side of the square is equal to that of the diameter of the circle, is:
( $\pi =\frac{22}{7}$ )
Option 1: 14 : 11
Option 2: 28 : 11
Option 3: 7 : 22
Option 4: 22 : 7
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Correct Answer: 14 : 11
Solution :
Let the side of the square (which is also the diameter of the circle) = $d$
The area of the square ($A_{\text{square}}$) = $d^2$
The area of the circle ($A_{\text{circle}}$) = $\pi r^2$, where $r$ is the radius of the circle.
Since the diameter of the circle is equal to the side of the square, the radius of the circle is $r = \frac{d}{2}$.
$A_{\text{circle}} = \pi \left(\frac{d}{2}\right)^2 = \frac{\pi d^2}{4}$
The ratio of the area of the square to the area of the circle is,
$\frac{A_{\text{square}}}{A_{\text{circle}}} = \frac{d^2}{\frac{\pi d^2}{4}} = \frac{4}{\pi}$
At $\pi = \frac{22}{7}$
$\frac{A_{\text{square}}}{A_{\text{circle}}} = \frac{4}{\frac{22}{7}} = \frac{28}{22} = \frac{14}{11}$
Hence, the correct answer is 14 : 11.
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