The value of (32)power 1(32)power1/6 (32)1/36....... is
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Given series = 32 32^1/6 32^1/36...........
=(32)^1+1/6+1/36+..........
The given series is in Geometric Progression...
Therefore,
Sum of Infinite GP = a/1-r
a=1,r=1/6
By substituting in the formula,we get
=1/ 1-1/6
=1/1-6
=6/5
Finally,we get,
=(32)^6/5
=16
Hope it helps you!!




