the value of i+ 2j - 3 k is parallel to 3i+ mj - 9k is

Hello there!

Greetings!

It's quite easy,  since both the vectors are parallel then for cetain value of a , we have,

i + 2j -3k= a (3i + mj -9k)...........(1)

Or, -3k = -9a k ( on equating k component of both the sides of the equation 1. )

or a =3 .....(2)

Also , 2j = ma j ( on equating j component of both the sides of equation 1.)

or 2j = m × 3×j (on putting the value a from 2) ,

or  m = 2/3 .

Thus , m = 2/3.

Thankyou

Hii

For parallel vectors, they can be expressed as

A=xB where A,B are vector and x is scalar.

So arranging them in this form we get

3i+mj-9k=3(i+2j-3k)

From this m=6

So the required solution is m=6 and x=3

Hope you understood,  if not comment down.

All the best