Question : The value of $\left(3^2\right)^2 + 3 \times 3 \div 3 - 3$ is:
Option 1: $3^2$
Option 2: $9^2$
Option 3: $2^3$
Option 4: $3^0$
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Correct Answer: $9^2$
Solution :
$\left(3^2\right)^2 + 3\times 3\div3 - 3$
$=\left(9\right)^2 + 3\times 3\div3 - 3$
$=81 + 3\times 3 \div3 - 3$
$= 81 + 3\times1 - 3$
$=81 + 3 -3$
$=81$
$ = 9^2$
Hence, the correct answer is $9^2$.
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