Question : The value of $\frac{1}{\sqrt{7-4 \sqrt{3}}}$ is closest to:
Option 1: 1.2
Option 2: 4.1
Option 3: 4.2
Option 4: 3.7
Correct Answer: 3.7
Solution :
$\frac{1}{\sqrt{7-4 \sqrt{3}}}$
$=\frac{1}{\sqrt{2^2+(\sqrt3)^2-2\times2\sqrt{3}}}$
$=\frac{1}{\sqrt{(2-\sqrt3)^2}}$
$=\frac{1}{(2-\sqrt3)}\times\frac{2+\sqrt3}{2+\sqrt3}$
$=\frac{2+\sqrt3}{4-3}$
$=2+\sqrt3$
= 2 + 1.732 = 3.732
Hence, the correct answer is 3.7.
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