Question : Three sets of 40, 50, and 60 students appeared for an examination and the pass percentages were 100, 90, and 80, respectively. The pass percentage of the whole set is:
Option 1: $88\frac{2}{3}\%$
Option 2: $84\frac{2}{3}\%$
Option 3: $88\frac{1}{3}\%$
Option 4: $84\frac{1}{3}\%$
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Correct Answer: $88\frac{2}{3}\%$
Solution :
Given:
Three sets of 40, 50, and 60 students appeared for an examination.
Total students = 40 + 50 + 60 = 150
The pass percentages were 100, 90, and 80, respectively.
So, passed students in 1st set = 40
passed students in 2nd set = $\frac{90}{100}$ × 50 = 45
passed students in 3rd set = $\frac{80}{100}$ × 60 = 48
Total passed students = 40 + 45 + 48 = 133
$\therefore$ Required percentage $=\frac{133}{150} × 100 = \frac{266}{3}=88\frac{2}{3}\%$
Hence, the correct answer is $88\frac{2}{3}\%$.
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