translate x= *p+&y into quadruples, triples.

Question

Question : The third proportional of the following numbers $(x-y)^2, (x^2-y^2)^2$ is:
Option 1: $(x+y)^3(x-y)^2$
Option 2: $(x+y)^4(x-y)^2$
Option 3: $(x+y)^2(x-y)^2$
Option 4: $(x+y)^2(x-y)^3$

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Answer 1

Hello Candidate,

Here are the general steps to convert any function into triplets- 1. Temporary Variables are not used, and references regarding the instructions are made.

Steps to convert a function into quadruples- op in the operator field, y in the arg1 field, x in the result field, arg2 field remains unused.

Hope that this information was helpful for you!!

Good good luck.

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Question : The third proportional of the following numbers $(x-y)^2, (x^2-y^2)^2$ is:
Option 1: $(x+y)^3(x-y)^2$
Option 2: $(x+y)^4(x-y)^2$
Option 3: $(x+y)^2(x-y)^2$
Option 4: $(x+y)^2(x-y)^3$

Question : Simplify the given expression $\frac{(x^3-y^3)(x+y)}{x^2+x y+y^2}$.
Option 1: $x - y$
Option 2: $x^2-y^2$
Option 3: $x + y$
Option 4: $x^2+y^2$

Question : The third proportional to $\left(x^2-y^2\right)$ and $(x-y)$ is:
Option 1: $(x -y)$
Option 2: $\frac{x-y}{x+y}$
Option 3: $\frac{x+y}{x-y}$
Option 4: $(x + y)$

Question : $\left(4 x^3 y-6 x^2 y^2+4 x y^3-y^4\right)$ can be expressed as:
Option 1: $(x+y)^4-x^4$
Option 2: $(x+y)^4-y^4$
Option 3: $(x-y)^4-x^4$
Option 4: $x^4-(x-y)^4$

Question : What is the simplified value of $\frac{(x+y+z)(x y+y z+z x)–x y z}{(x+y)(y+z)(z+x)}$?
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Option 2: $z$
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