Question : Two baskets together have 640 oranges. If $\left (\frac{1}{5} \right)^{th}$ of the oranges in the first basket are taken to the second basket then, the number of oranges in both the baskets becomes equal. The number of oranges in the first basket is:

Option 1: 800

Option 2: 600

Option 3: 400

Option 4: 300

Question : Directions: Which of the following numbers will replace the question mark (?) in the given series?
$\left [ \frac{1}{176} \right ],\left [ \frac{1}{88} \right ],?,\left [ \frac{1}{22} \right ],\left [ \frac{1}{11} \right ]$

Option 1: $\left[\frac{1}{32}\right]$

Option 2: $\left\lceil\frac{1}{44}\right]$

Option 3: $\left\lceil\frac{1}{48}\right]$

Option 4: $\left\lceil\frac{1}{42}\right]$

Question : If $\sec \theta+\tan \theta=5, (\theta \neq 0)$, then $\sec \theta$ is equal to:

Option 1: $\left(5+\frac{1}{5}\right)$

Option 2: $\frac{1}{2}\left(3+\frac{1}{3}\right)$

Option 3: $\frac{1}{2}\left(5+\frac{1}{5}\right)$

Option 4: $\left(3+\frac{1}{3}\right)$

Question : Find the sum of $\left (1-\frac{1}{n+1} \right) + \left (1-\frac{2}{n+1} \right) + \left (1- \frac{3}{n+1} \right)+.....\left ( 1- \frac{n}{n+1} \right)$.

Option 1: $n$

Option 2: $\frac{n}{2}$

Option 3: $(n+1)$

Option 4: $\frac{(n+1)}{2}$

Question : If $M =\left ( \frac{3}{7} \right ) ÷ \left ( \frac{6}{5} \right ) ×\left ( \frac{2}{3} \right ) + \left ( \frac{1}{5} \right ) ×\left ( \frac{3}{2} \right )$ and $N = \left ( \frac{2}{5} \right ) × \left ( \frac{5}{6} \right ) ÷ \left ( \frac{1}{3} \right ) + \left ( \frac{3}{5} \right ) × \left ( \frac{2}{3} \right ) ÷ \left ( \frac{3}{5} \right )$,
then what is the value of $\frac{M}{N}$?

Option 1: $\frac{207}{560}$

Option 2: $\frac{339}{1120}$

Option 3: $\frac{113}{350}$

Option 4: $\frac{69}{175}$

Question : The value of $\left(2 \frac{6}{7}\right.$ of $\left.4 \frac{1}{5} \div \frac{2}{3}\right) \times 5 \frac{1}{9} \div\left(\frac{3}{4} \times 2 \frac{2}{3}\right.$ of $\left.\frac{1}{2} \div \frac{1}{4}\right)$ is:

Option 1: 25

Option 2: 19

Option 3: 23

Option 4: 21