two particles are projected horizontally from the same elevated positions in opposite directions
Answer (1)
Student Expert
26th Nov, 2019
Hello there!
Greetings!
Although you haven't completed your question but I guess the question is asking to find the time when the two velocities are at 90 degree.
Now , to solve the problem let ( 3, v1) be first velocity and (-4,v2) be second velocity
Then,
V1 = v2= get = 10t
(3,10t) * (-4,10t) =0
-12 + 100t^2 = 0
t = (0.12)^1/2s i.e root 0.12 s.
Thankyou
Greetings!
Although you haven't completed your question but I guess the question is asking to find the time when the two velocities are at 90 degree.
Now , to solve the problem let ( 3, v1) be first velocity and (-4,v2) be second velocity
Then,
V1 = v2= get = 10t
(3,10t) * (-4,10t) =0
-12 + 100t^2 = 0
t = (0.12)^1/2s i.e root 0.12 s.
Thankyou
Comments (0)
Related Questions
Trending Articles/News
![CAT Result 2025: Release Date, Scorecard Download [Direct Link] iimcat.ac.in, Percentile Calculation & Cutoffs](https://cache.careers360.mobi/media/presets/50X50/article_images/2025/11/21/CAT Result Date 2025.jpg)
