Two tall buildings are 200 m apart ,with what speed must a ball be thrown horizontally from a window 540 m above the ground in one building so as to enter a 50 m high window in the other building
Hi,
So the height drops from 540 m to 50 m window,
Height drop = 540 m - 50 m = 490 m
Using the free-fall formula, Time of fall:
t = square root of (2h / g) [where g = 9.8 ]
t = 10s
We know that, the buildings are 200 apart.
Thus,
speed = Distance / time
speed = 200 / 10
Therefore,
Horizontal speed = 20 m / s
Hi,
So the height drops from 540 m to 50 m window,
Height drop = 540 m - 50 m = 490 m
Using the free-fall formula, Time of fall:
t = square root of (2h / g) [where g = 9.8 ]
t = 10s
We know that, the buildings are 200 apart.
Thus,
speed = Distance / time
speed = 200 / 10
Therefore,
Horizontal speed = 20 m / s
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