Question : What is the expansion of $(2+\frac{1}{p})^2$?
Option 1: $4+\frac{4}{p}+\frac{1}{p^2}$
Option 2: $2+\frac{2}{p}+\frac{1}{p^2}$
Option 3: $2+\frac{4}{p}+\frac{1}{p^2}$
Option 4: $4+\frac{2}{p}+\frac{1}{p^2}$
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Correct Answer: $4+\frac{4}{p}+\frac{1}{p^2}$
Solution :
Given: $(2+\frac{1}{p})^2$
$=2^2+\frac{1}{p^2}+2\times2\times\frac{1}{p}$
$=4+\frac{1}{p^2}+\frac{4}{p}$
Hence, the correct answer is $4+\frac{4}{p}+\frac{1}{p^2}$.
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