What is the gravitational potential energy of an object located 20,000 m above the earth's surface ? 1. U = - GMm/ (20km + Re) 2. U= - GMm / ( 20000km + Re) 3. U = - GMm / Re 4. U = -GMm/ (Re-20km)
Answer (1)
22nd Dec, 2019
Santosh, the correct answer is Option 1- GMm/(Re + 20km).
Potential energy at height 'h' from the surface of the Earth is the work done by an external agent to bring an object of mass 'm' from infinity to that point without any change in its kinetic energy.
The formula for potential energy is: GMm/R, where R = Re + h. Re refers to the radius of the Earth and h refers to the height above the Earth's surface. So substituting h with 20000m or 20km, we get the answer as Option 1.
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