What is the minimum Mark's required for clearing jee mains 2019

Last year's ( 2018 ) cutoffs for qualifying JEE Main is:

Common rank list - 350 (Maximum) - 74 (Minimum)

OBC  NCL - 45 minimum

SC - 29 Minimum

ST - 24 Minimum

For 2017

General - 81 minimum

OBC NCL - 49

SC - 32

ST - 27

Cutooff for this year will be released within this month along with the results

Hello,

The Precise cut off of JEE Mains 2019 cannot be declared right now but you can still have an idea about what the expected cutoff for this year is.

The cut off of JEE Main 2018 was 74 (general), 45 (OBC), 29 (SC) and 24 (ST). From the year 2019, there will be two exams for JEE Main 2019, therefore the cut off can either increase or decrease depending on the normalization procedure of NTA. However, it is likely to be around these numbers only.

Hope it helps.