What is the minimum Mark's required for clearing jee mains 2019
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Last year's (
2018
) cutoffs for qualifying JEE Main is:
Common rank list - 350 (Maximum) - 74 (Minimum)
OBC NCL - 45 minimum
SC - 29 Minimum
ST - 24 Minimum
For
2017
General - 81 minimum
OBC NCL - 49
SC - 32
ST - 27
Cutooff for this year will be released within this month along with the results
The Precise cut off of JEE Mains 2019 cannot be declared right now but you can still have an idea about what the expected cutoff for this year is.
The cut off of JEE Main 2018 was 74 (general), 45 (OBC), 29 (SC) and 24 (ST). From the year 2019, there will be two exams for JEE Main 2019, therefore the cut off can either increase or decrease depending on the normalization procedure of NTA. However, it is likely to be around these numbers only.
Hope it helps.
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