what is the minimum percentile base on paper 1 in jee (main) 2020 to get admission into kaziranga university (assam)

Hello Aspirant,

Since the cut offs are not yet released. I'm giving you previous year cut offs. Gen:89.7548849

Ews:78.2174869

Obc:74.3166997

Sc:54.0128155

ST:44.3345172

Pwd:0.1137130. Firstly, according to your category you need to fulfill the above .And then based on your rank and home state you can know whether you will get seat or not.This year total 869010 students attempted jee January. In april 1200000 students are going to attempt. You can calculate your approximate rank using formula (100-percentile)*students attempted /100. You can use below link for kaziranga university :

https://www.google.com/amp/s/www.careers360.com/university/the-assam-kaziranga-university-jorhat

You can use below link for all nits cut offs:

https://www.google.com/url?sa=t&source=web&rct=j&url=https://engineering.careers360.com/articles/nits-cutoff-for-top-btech-branches/amp&ved=2ahUKEwiSnqjEyMznAhXFyDgGHUt_CE8QFjAEegQIBxAB&usg=AOvVaw2OXl9cMS4B7GJ9DfTIJZCg&ampcf=1

If you want to predict colleges for your percentile use below :

https://engineering.careers360.com/jee-main-college-predictor