#Class 12

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What is the open rank for 98.3 percentile

Ravikiran 26th Mar, 2019

Answer (1)

Praneeth Gupta 26th Mar, 2019

Hello ravikiran

Your rank as per your percentile of 98.3 ranges from 14,000 to 15,000.And you calculate your rank by using the following formula-

JEE Main 2019 rank = (100- NTA percentile score ) X 874469 /100

For more accuracy you can visit the link-https://engineering.careers360.com/jee-main-rank-predictor.

Hope this was helpful!!

All the best!!!

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27th Mar, 2019

Is it got the seat ECE in Warangal nit

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