Question : What is the remainder when $\left(x^{17}+1\right)$ is divided by $(x+1)$?
Option 1: $x$
Option 2: $x - 1$
Option 3: $0$
Option 4: $1$
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Correct Answer: $0$
Solution :
$\left(x^{17}+1\right)$ is divided by $(x +1)$
$P(x) = \left(x^{17}+1\right)$
Divisor = $x + 1$
$\therefore$ remainder = $P(- 1) = (- 1)^{17}+ 1= - 1 + 1 = 0$
Hence, the correct answer is $0$.
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