which is the minimum best college I would get admission to with my 98.65 percentile in JEE mains paper 2
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Hello,
If we use the below formula we will get your approximated rank
100 - your total percentile score is the percentage of people ahead of you. 112679 are the number of candidates appeared for January exam.
So rank formula is (100 - your total score) X 112679 /100.
Your approximated rank is 1521. As you haven't mentioned your category nor your home state so please click the below link to know about the previous year cutoff so that you could predict which college in NITs you can get.
https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning
Hello Annena Mariya,
First of all congrats for your good result. you need to provide your category and home state, because the cut-offs and ranks varies for home state guys and other states.
you can predict your rank using the formula: (100-your total score)*112679/100 and here 112679 is the number of candidates applied for the jan exam and this changes after the april exam due to increase in number of students.
and you can use the careers360 college predictor to get to know your colleges:
and you can use the below link for further reference:
https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning
hope it helps.
All the best.
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