WILL I GET CSE BRANCH IN ANY BIHAR ENGINEERING COLLEGE.. MY JEE MAINS SCORE IS 82.5 PERCENTILE(OBC)??
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Hello Ankur
864469 are the number of candidates appeared for the January exam. So rank formula is (100- your total score) * 864469 / 100.
If you consider this then your rank will be around 1.4-1.5 L.
With this rank CSE is pretty difficult.
For more info: https://engineering.careers360.com/articles/jee-main-cutoff
Reply
https://engineering.careers360.com/articles/jee-main-cutoff
Now since you day you are from bihar you might wanna take a look at the cutoffs of NIT Patna
https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-patna
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