WILL I GET CSE BRANCH IN ANY BIHAR ENGINEERING COLLEGE.. MY JEE MAINS SCORE IS 82.5 PERCENTILE(OBC)??
Answers (2)
Student Expert
21st Jan, 2020
Hello Ankur
864469 are the number of candidates appeared for the January exam. So rank formula is (100- your total score) * 864469 / 100.
If you consider this then your rank will be around 1.4-1.5 L.
With this rank CSE is pretty difficult.
For more info: https://engineering.careers360.com/articles/jee-main-cutoff
1 Comment
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21st Jan, 2020
In the following link you will find the expected cutoff for the 2020 for all NITs and you'll also find the previous year cutoffs
https://engineering.careers360.com/articles/jee-main-cutoff
Now since you day you are from bihar you might wanna take a look at the cutoffs of NIT Patna
https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-patna
https://engineering.careers360.com/articles/jee-main-cutoff
Now since you day you are from bihar you might wanna take a look at the cutoffs of NIT Patna
https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-patna
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