BITS Pilani- Hyderabad Campus, Hyderabad
Hi Rudra Viroja,
Admission to B.Tech programs at BITS Pilani Hyderabad, including those for students with a diploma, is primarily through BITSAT i.e. BITS Admission Test. There is no direct lateral entry into the second year for diploma holders. Candidates must qualify in BITSAT and meet the minimum eligibility criteria, which includes passing the 12th examination with Physics, Chemistry, and Mathematics/Biology from a recognized board, with specific marks in each subject and a minimum aggregate.
Admission process includes,
Below mentioned is the BITS Hyd. official link where you can check out the details like when will the form release and etc.
https://www.bits-pilani.ac.in/admission-process-flow/
Kindly refer to the below mentioned link for further information about the exam and admission process.
https://www.careers360.com/colleges/bits-pilani-hyderabad-campus-hyderabad/admission
I hope this helps.
Here is the detailed admission process,
Candidates seeking admission shall first check the course-specific eligibility criteria. Eligible students can further fill out the application form for the respective course/or the required examination.
BITS Hyderabad offers admission to BTech/BE/BPharm/MSc courses is based on merit in BITSAT [BITS Admission test]. Candidates qualifying for the exam are further called for counselling.
Below is the official website of BITS Hyderabad campus. Here you can find the application form.
Hello aspirant,
Students at BITS Hyderabad can choose from a variety of curricula and receive attractive packages for employment in reputable companies. The placement process at BITS Hyderabad begins with the institute sending out invitations to firms for the placement drive, and the companies then choose individuals based on their placement procedures. The placement drive is held twice a year by the institute, from August to November and January to April. BITS Hyderabad Pilani has a stellar placement history.
To know the 2023 placement, you can visit our website by clicking on the link given below.
https://www.careers360.com/colleges/bits-pilani-hyderabad-campus-hyderabad/placement
Thank you
Hope this information helps you.
Question : The value of $\frac{4 \tan ^2 30^{\circ}+\sin ^2 30^{\circ} \cos ^2 45^{\circ}+\sec ^2 48^{\circ}-\cot ^2 42^{\circ}}{\cos 37^{\circ} \sin 53^{\circ}+\sin 37^{\circ} \cos 53^{\circ}+\tan 18^{\circ} \tan 72^{\circ}}$ is:
Option 1: $\frac{35}{48}$
Option 2: $\frac{59}{48}$
Option 3: $\frac{49}{24}$
Option 4: $\frac{35}{24}$
Correct Answer: $\frac{59}{48}$
Solution : Given: $\frac{4 \tan ^2 30^{\circ}+\sin ^2 30^{\circ} \cos ^2 45^{\circ}+\sec ^2 48^{\circ}-\cot ^2 42^{\circ}}{\cos 37^{\circ} \sin 53^{\circ}+\sin 37^{\circ} \cos 53^{\circ}+\tan 18^{\circ} \tan 72^{\circ}}$ We know that $\tan 30^{\circ} = \frac{1}{\sqrt{3}}$ $\sin 30^{\circ} = \frac{1}{2}$ $\cos 45^{\circ} = \frac{1}{\sqrt{2}}$ $\cos 37^{\circ} = \cos (90^{\circ} - 53^{\circ}) = \sin 53^{\circ}$ $\sin 37^{\circ} = \sin (90^{\circ} - 53^{\circ}) = \cos 53^{\circ}$ $\tan 18^{\circ} \tan 72^{\circ} = 1$ (since $18^{\circ}$ and $72^{\circ}$ are complementary angles) Putting the values, we get: $= \frac{4 (\frac{1}{\sqrt{3}})^2 + (\frac{1}{2})^2 (\frac{1}{\sqrt{2}})^2 + \sec ^2 48^{\circ} - \tan ^2 48^{\circ}}{\sin 53^{\circ} \sin 53^{\circ} + \cos 53^{\circ} \cos 53^{\circ} + 1}$ $= \frac{4 (\frac{1}{3}) + \frac{1}{8} +1}{(\sin ^2 53^{\circ} + \cos ^2 53^{\circ}) + 1}$ Since $\sin ^2 \theta + \cos ^2 \theta = 1$ for any angle $\theta$, the denominator becomes $1 + 1 = 2$. So, the expression simplifies to: $=\frac{4 (\frac{1}{3}) + \frac{1}{8} + 1}{2}$ $=\frac{ (\frac{4}{3}) + \frac{1}{8} + 1}{2}$ $=\frac{ (\frac{32+3+24}{24}) }{2}$ $=(\frac{59}{48})$ Hence, the correct answer is $(\frac{59}{48})$.
The Goa Board HSSC 2023 syllabus is essential for students studying for their class 12 exams since it contains the topics and units they must cover. Knowing the www.gbshse.gov.in curriculum 2023–24 would enable them to streamline their preparation process. The 'Study Material' section of gbshse.info will provide the Goa Board 12th 2023–24 course syllabus.
To know complete exam syllabus, you can visit our site by clicking on the link given below.
https://school.careers360.com/boards/gbshse/goa-board-hssc-syllabus
Hello,
I would suggest you to refer to the link below to check the fee structure-
http://www.bitsadmission.com/fdmain.aspx#feeschedule
Good luck!
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Hello Naaz,
No, you cannot get admission to BITS directly. The direct admission procedure is for the board toppers. Others have to take up the BITSAT Exam.
ELIGIBILITY CRITERIA:
Passed 10+2 examination from a recognised board with at least 60% in aggregate and must have studied Physics, Chemistry and Mathematics and scored an aggregate of 75% marks in PCM.
ADMISSION PROCESS:
To know more about this college, visit:
https://www.careers360.com/colleges/bits-pilani-hyderabad-campus-hyderabad
Hello Raghvendra,
The cutoff of all the three campuses of BITS are as follows:
PILANI CAMPUS CUTOFF:
BE Chemical Engineering- 281
BE Civil Engineering- 269
BE Computer Science Engineering- 383
BE Electrical and Electronics Engineering- 341
BE Electronics and Instrumentation Engineering- 328
BE Manufacturing Engineering- 255
BE Mechanical Engineering- 313
At Pilani campus, you can get Chemical Engineering, Civil Engineering, and Manufacturing Engineering if we go by last year trends.
HYDERABAD CAMPUS CUTOFF:
BE Chemical Engineering- 252
BE Civil Engineering- 254
BE Computer Science Engineering- 342
BE Electrical and Electronics Engineering- 308
BE Electronics and Communication Engineering- 318
BE Electronics and Instrumentation Engineering- 294
BE Mechanical Engineering- 275
At the Hyderabad campus, you can get Chemical Engineering, Civil Engineering, and Mechanical Engineering if we go by the previous year's trend.
GOA CAMPUS CUTOFF:
BE Chemical Engineering- 254
BE Computer Science Engineering- 352
BE Electrical and Electronics Engineering- 310
BE Electronics and Communication Engineering- 322
BE Mechanical Engineering- 280
At the Hyderabad campus, you can get Chemical Engineering, and Mechanical Engineering if we go by the previous year's trend.
However, cutoffs vary a lot so, you might also get some more branches with your score. The prediction cannot be 100% true due to the varying cutoffs. But, you can get a rough idea about the branches that you can expect at all these campuses.
To use the BITSAT college predictor tool, visit:
https://www.careers360.com/bitsat-college-predictor
If you are enquiring about Birla Institute of Science and Technology Hyderabad campus then here is the cut off for BITSAT 2020 to get admission in to BITS, Hyderabad
Considering the cut off you do not have chances to get seat in BITS, Hyderabad. You need to score minimum 240 marks or above to have decent chances of getting seat. Cut off is subjected to change it may increase or decrease depending on the total number of candidates applied, difficulty level of examination and total number of seats available etc. To check the cut off click use the link given below
https://www.bitsadmission.com/bitsat/2022/BITSAT2022MAR14.pdf
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